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<meta property="og:description" content="homework_8 (1)
输入一个目标数字，将其绝对值记做余数
余数 &gt; 0
​ 将余数➗16的商加到字符串的末尾（超过10需转换为A&hellip;F）
​ 将余数=自身➗16的余数
结束
IF 目标数字&lt;0
THEN 输出符号
输出字符串
(2)//
// main.c
// testc
//
// Created by 严旭 on 2020/10/9.
//
#include &lt;stdio.h&gt;
#include&lt;string.h&gt;
char ans[100];
int top=0;
int main(){
int d,temp,r;
scanf(&quot;%d&quot;,&amp;temp);//输入目标数字
if(temp==0){
​ printf(&ldquo;0\n&rdquo;);
​ return 0;
}
if(temp&lt;0){
​ d=-temp;
}else{
​ d=temp;
}//取目标数字绝对值d
while(d&gt;0){//计算d/16,余数转换后填入结果，商赋给d，直到d==0；
​ r=d%16;
​ d=d/16;
​ if(r&lt;10){
​ ans[top&#43;&#43;]=r&#43;&lsquo;0&rsquo;;
​ }else{
​ switch(r){
​ case 10: ans[top&#43;&#43;]=&lsquo;a&rsquo;;break;" />
<meta property="og:type" content="article" />
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<meta itemprop="description" content="homework_8 (1)
输入一个目标数字，将其绝对值记做余数
余数 &gt; 0
​ 将余数➗16的商加到字符串的末尾（超过10需转换为A&hellip;F）
​ 将余数=自身➗16的余数
结束
IF 目标数字&lt;0
THEN 输出符号
输出字符串
(2)//
// main.c
// testc
//
// Created by 严旭 on 2020/10/9.
//
#include &lt;stdio.h&gt;
#include&lt;string.h&gt;
char ans[100];
int top=0;
int main(){
int d,temp,r;
scanf(&quot;%d&quot;,&amp;temp);//输入目标数字
if(temp==0){
​ printf(&ldquo;0\n&rdquo;);
​ return 0;
}
if(temp&lt;0){
​ d=-temp;
}else{
​ d=temp;
}//取目标数字绝对值d
while(d&gt;0){//计算d/16,余数转换后填入结果，商赋给d，直到d==0；
​ r=d%16;
​ d=d/16;
​ if(r&lt;10){
​ ans[top&#43;&#43;]=r&#43;&lsquo;0&rsquo;;
​ }else{
​ switch(r){
​ case 10: ans[top&#43;&#43;]=&lsquo;a&rsquo;;break;">

<meta itemprop="wordCount" content="214">



<meta itemprop="keywords" content="" />
<meta name="twitter:card" content="summary"/>
<meta name="twitter:title" content=""/>
<meta name="twitter:description" content="homework_8 (1)
输入一个目标数字，将其绝对值记做余数
余数 &gt; 0
​ 将余数➗16的商加到字符串的末尾（超过10需转换为A&hellip;F）
​ 将余数=自身➗16的余数
结束
IF 目标数字&lt;0
THEN 输出符号
输出字符串
(2)//
// main.c
// testc
//
// Created by 严旭 on 2020/10/9.
//
#include &lt;stdio.h&gt;
#include&lt;string.h&gt;
char ans[100];
int top=0;
int main(){
int d,temp,r;
scanf(&quot;%d&quot;,&amp;temp);//输入目标数字
if(temp==0){
​ printf(&ldquo;0\n&rdquo;);
​ return 0;
}
if(temp&lt;0){
​ d=-temp;
}else{
​ d=temp;
}//取目标数字绝对值d
while(d&gt;0){//计算d/16,余数转换后填入结果，商赋给d，直到d==0；
​ r=d%16;
​ d=d/16;
​ if(r&lt;10){
​ ans[top&#43;&#43;]=r&#43;&lsquo;0&rsquo;;
​ }else{
​ switch(r){
​ case 10: ans[top&#43;&#43;]=&lsquo;a&rsquo;;break;"/>

	
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      <h1 class="f1 athelas mt3 mb1"></h1>
      
      
      <time class="f6 mv4 dib tracked" datetime="0001-01-01T00:00:00Z">January 1, 0001</time>

      
      
    </header>
    <div class="nested-copy-line-height lh-copy serif f4 nested-links nested-img mid-gray pr4-l w-two-thirds-l"><h2 id="homework_8">homework_8</h2>
<p>(1)</p>
<p>输入一个目标数字，将其绝对值记做余数</p>
<p>余数 &gt; 0</p>
<p>​       将余数➗16的商加到字符串的末尾（超过10需转换为A&hellip;F）</p>
<p>​        将余数=自身➗16的余数</p>
<p>结束</p>
<p>IF 目标数字&lt;0</p>
<p>THEN  输出符号</p>
<p>输出字符串</p>
<p>(2)//</p>
<p>// main.c</p>
<p>// testc</p>
<p>//</p>
<p>// Created by 严旭 on 2020/10/9.</p>
<p>//</p>
<p>#include &lt;stdio.h&gt;</p>
<p>#include&lt;string.h&gt;</p>
<p><strong>char</strong> ans[100];</p>
<p><strong>int</strong> top=0;</p>
<p><strong>int</strong> main(){</p>
<p><strong>int</strong> d,temp,r;</p>
<p>scanf(&quot;%d&quot;,&amp;temp);//输入目标数字</p>
<p><strong>if</strong>(temp==0){</p>
<p>​    printf(&ldquo;0\n&rdquo;);</p>
<p>​    <strong>return</strong> 0;</p>
<p>}</p>
<p><strong>if</strong>(temp&lt;0){</p>
<p>​    d=-temp;</p>
<p>}<strong>else</strong>{</p>
<p>​    d=temp;</p>
<p>}//取目标数字绝对值d</p>
<p><strong>while</strong>(d&gt;0){//计算d/16,余数转换后填入结果，商赋给d，直到d==0；</p>
<p>​    r=d%16;</p>
<p>​    d=d/16;</p>
<p>​    <strong>if</strong>(r&lt;10){</p>
<p>​      ans[top++]=r+&lsquo;0&rsquo;;</p>
<p>​    }<strong>else</strong>{</p>
<p>​      <strong>switch</strong>(r){</p>
<p>​        <strong>case</strong> 10: ans[top++]=&lsquo;a&rsquo;;<strong>break</strong>;</p>
<p>​        <strong>case</strong> 11: ans[top++]=&lsquo;b&rsquo;;<strong>break</strong>;</p>
<p>​        <strong>case</strong> 12: ans[top++]=&lsquo;c&rsquo;;<strong>break</strong>;</p>
<p>​        <strong>case</strong> 13: ans[top++]=&rsquo;d';<strong>break</strong>;</p>
<p>​        <strong>case</strong> 14: ans[top++]=&lsquo;e&rsquo;;<strong>break</strong>;</p>
<p>​        <strong>case</strong> 15: ans[top++]=&lsquo;f&rsquo;;<strong>break</strong>;</p>
<p>​      }</p>
<p>​    }</p>
<p>}</p>
<p><strong>if</strong>(temp&lt;0) printf(&quot;-&quot;);</p>
<p><strong>for</strong>(<strong>int</strong> i = top-1; i &gt;=0;i&ndash;)</p>
<p>printf(&quot;%c&quot;,ans[i]);//输出</p>
<p>printf(&quot;\n&quot;);</p>
<p><strong>return</strong> 0;</p>
<p>}</p>
<p>（3）输出 -1 0 1 f 1a cc1</p>
<p>2.(1)</p>
<p>Top-down design: It starts out by defining the solution at the level of functionality and breaking it down further and further into small routines that can be easily documented and coded.</p>
<p>(2)work breakdown struture</p>
<p>A work breakdown structure, in project management and systems engineering, is a deliverable-oriented decomposition of a project into smaller components.</p>
<p>(3) 同:两者都将整体分成小块处理</p>
<p>​     异:top-down design 分得更细。</p>
<ol start="3">
<li></li>
</ol>
<p>(1)</p>
<p>注水</p>
<p>浸泡</p>
<p>转动</p>
<p>排水</p>
<p>结束</p>
<p>(2)</p>
<p>IF water_in_switch(true)返回为真</p>
<p>THEN IF time_counter() == 规定浸泡时间</p>
<p>THEN</p>
<p>WHILE time_counter()-规定浸泡时间 &lt; 规定转动时间</p>
<p>​     motor_run(left);</p>
<p>​     motor_run(right);</p>
<p>结束</p>
<p>IF water_out_switch(open)返回为真</p>
<p>halt(true)</p>
<p>ELSE halt(false);</p>
<p>(3)步骤相同，但浸泡时间和转动时间不同</p>
<p>(4)转动(time)//在指定时间内进行持续进行转动行为</p>
<p>注水</p>
<p>等待</p>
<p>转动</p>
<p>排水</p>
<p>结束</p>
<ul class="pa0">
  
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